<
From version < 50.1 >
edited by StruSoft Developers
on 2019/05/09 13:19
To version < 50.2 >
edited by StruSoft Developers
on 2019/05/09 13:21
>
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... ... @@ -632,8 +632,35 @@
632 632  (% style="text-align: justify;" %)
633 633  ε,,sm,, - ε,,cm,, may be calculated from the expression:
634 634  
635 +[[image:1557399634681-893.png||height="66" width="360"]]
635 635  
637 +where:
636 636  
639 +**σ,,s,,** is the tension reinforcement assuming a cracked section,
640 +
641 +**α,,e,,** is the ratio E,,s,, / E,,cm,,
642 +
643 +**ρ,,p,eff,,**,, ,,= A,,s,, / A,,c,eff,,,
644 +
645 +**A,,c,eff,,** is calculated as below,
646 +
647 +**k,,t,,** is a factor dependent on the duration of the load,
648 +
649 +**k,,t,,** = 0,6 for short term loading,
650 +
651 +**k,,t,, **= 0,4 for long term loading (always supposed by the program),
652 +
653 +**A,,c,eff,,**:
654 +
655 +[[image:1557400792364-457.png||height="154" width="522"]]
656 +
657 +
658 +hc,ef = min (2,5 (h - d), (h - x) / 3, h / 2) sr,max = k3 c + k1 k2 k4 φ / ρp,eff
659 +where: φ is the bar diameter. Where a mixture of bar diameters is used in a section, an equivalent diameter, φeq, should be used. For a sec- tion with n1 bars of diameter φ1 and n2 bars of diameter φ2, the following expression should be used,
660 +
661 +
662 +
663 +
637 637  == Stirrups ==
638 638  
639 639  === Shear ===
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